Example questions
1 1) Two converging lenses are to be placed in the path of
parallel rays so that the rays remain parallel after passing through both
lenses. How should the lenses be arranged? Explain with a neat ray diagram.
ANS:
i) A parallel beam
of light rays will converge on focal point of the lens after refraction.
ii) Light rays
passes through the focal point will parallel to principal axis after
re-fraction.
iii) So the two
lenses are arranged on a common
principal axis such that their focal points coincide with each other, then the
rays remain parallel after passing through both lenses.
2 2) The focal length of a converging lens is 20cm. An object is
60cm from the lens. Where will the image be formed and what kind of image is
it?
ANS: Given, f=20 cm
U=-60cm
Lens formula
1/f=1/v-1/u
1/20=1/v-(1/-60)
1/20=1/v+1/60
1/v=1/20-1/60
1/v= (3-1)/60 [L.C.M]
1/v=2/60
1/v=1/30
Therefore v=30 cm
3 3) A double convex lens has two surfaces of equal radii ‘R’ and
refractive index n = 1.5. Find the focal length ‘f’.
ANS: Given
Radius of
curvature =R
focal length =f
Refractive
index, μ=1.5
From lens maker's
formula
f1=(μ−1)[1/R1-1/R2]
f1=(1.5−1)[1/R+1/R]
=0.5×2/R
1/f=1/R
f=R
4)
A convex lens is made up of three different materials as
shown in the figure. How many of images does it form?
ANS: The answer is very simple number of images formed by a
lens is equal to the number of different materials used to make the lens.
So, in the
above example the number of images formed are three.
5) Find the radii of curvature of a convexo
–concave convergent lens made of glass with refractive index n=1.5 having focal
length of 24cm. One of the radii of curvature is double the other.
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